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Complex conjugation

If we denote $\bar{a}$ as the complex conjugate of $a$, we have $$\bar{a\bar{b}}=\overline{\bar{a}b}=\overline{ab}$$ But $$\bar{a\bar{b}}=\overline{ab}+i\overline{b\bar{a}}$$
Why the $\bar{a}$ comes to the right side of the last equation?

A:

$$\bar{a\bar{b}}=\overline{ab}+i\overline{b\bar{a}}$$
Here we are taking the complex conjugate of both the sides. So
$$\bar{a\bar{b}}=\overline{(\bar{a}+i\bar{b})(\bar{a}-i\bar{b})}$$
$$\bar{a\bar{b}}=\overline{\bar{a}\bar{b}+i\bar{b}\bar{a}}$$
$$\bar{a\bar{b}}=\overline{a\bar{b}+i\bar{b}\bar{a}}$$
$$\bar{a\bar{b}}=\overline{ab+i(b\bar{a}-a\bar{b})}$$
$$\bar{a\bar{b}}=\overline{ab}+i\overline{b\bar{a}}$$
$$\bar{a\bar{b}}=\overline{ab}+i\overline{b\bar{a}}$$
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